IMPORTANT NOTE: This CASA section cantains word for word CASA samples. However they are several years old. There is still very valuable learning in the type of wording they use, but our RPL PPL and CPL sections are far more up to date and exam relevant.
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When shall an Air Safety Incident Report be submitted?
A pilot of a flight, over land, within an ADIZ shall immediately notify ATS of a deviation from track of plus or minus:
Within an ADIZ, an intercepting aircraft performs a climbing turn of 90 degrees or more, without crossing the line of flight of the intercepted aircraft. This means:
You should respond by rocking the wings at either day or night.
You should respond by rocking the wings at either day or night.
Which statement correctly specifies the conditions under which the pilot of a VFR flight is required to obtain and study a meteorological forecast before beginning a flight?
This is a recent change in 2021.
This is a recent change in 2021.
11 US gph converted to litres/hr is closest to:
The conversion tables are located in AIP GEN and The VFRG.
The conversion tables are located in AIP GEN and The VFRG.
Given: W/V = 250M/30. Runways available are 03/21 and 09/27. Which runway has the greatest headwind component for landing?
Which of the following will increase the landing distance when using an asphalt runway?
The length of runway which is available and suitable for the ground run of an aeroplane taking off is called the:
This is the actual take-off ground run of pavement available to an aircraft for take-off. It is different to the take-off distance available.
This is the actual take-off ground run of pavement available to an aircraft for take-off. It is different to the take-off distance available.
The product of the weight of an item and its horizontal distance from the datum is called the:
Moment = Force x Arm
Moment = Force x Arm
An effect of loading an aeroplane with its centre of gravity forward of the forward limit is that:
This will mean the aircraft has less controllability and larger control inputs are required to change the aircraft’s attitude.
An aircraft can be too stable. If an aircraft is too stable, it won’t respond much (or not at all) to control inputs. It will not have much controllability.
This will mean the aircraft has less controllability and larger control inputs are required to change the aircraft’s attitude.
An aircraft can be too stable. If an aircraft is too stable, it won’t respond much (or not at all) to control inputs. It will not have much controllability.
The maximum speed at which full or abrupt control movements can be safely made during normal flight is called the:
Below the manoeuvring speed, a full abrupt application of the controls will result in a stall before the aircraft exceeds structural limits. Above this speed, the aircraft will exceed structural details.
Below the manoeuvring speed, a full abrupt application of the controls will result in a stall before the aircraft exceeds structural limits. Above this speed, the aircraft will exceed structural details.
The beginning of daylight in UTC at FORREST WA (3050S 12807E) on the 7th February is closest to:
ARC to time = 0832
LMT = 0508
0508 – 0832 = 062036Z
Therefore, the answer of 062034 is closest.
ARC to time = 0832
LMT = 0508
0508 – 0832 = 062036Z
Therefore, the answer of 062034 is closest.
Given:
Beginning of daylight HAY (3432S 14450E) is 0615LMT;
End of daylight AYERS ROCK (2512S 13059E) is 1715LMT;
Planned landing time is 30 minutes before end of daylight.
What is the approximate time available, for a VFR flight from HAY to AYERS ROCK if the planned landing time is to be achieved?
Step One: Take the longitude of HAY (144 50) and convert to UTC TIME using the ARC TO TIME CHART (In this case 9 Hours 39 Minutes). This gives a UTC time for BOD of 2036.
Step Two: Take the longitude of AYERS ROCK (130 59) and convert to UTC using ARC TO TIME CHART (In this case 8 Hours 44 Minutes). This gives a UTC time for EOD of 0831.
Step Three: Now that you have both the beginning and end of daylight in UTC, work out the difference between the two times, in this case 11 hours 55 minutes. All that’s left to do then is minus the 30 minutes from this time as stated in the question. This gives the final answer of 11 hours and 25 minutes.
See our guide: RPL-PPL-Light-And-Time-Guide (opens in new tab)
Step One: Take the longitude of HAY (144 50) and convert to UTC TIME using the ARC TO TIME CHART (In this case 9 Hours 39 Minutes). This gives a UTC time for BOD of 2036.
Step Two: Take the longitude of AYERS ROCK (130 59) and convert to UTC using ARC TO TIME CHART (In this case 8 Hours 44 Minutes). This gives a UTC time for EOD of 0831.
Step Three: Now that you have both the beginning and end of daylight in UTC, work out the difference between the two times, in this case 11 hours 55 minutes. All that’s left to do then is minus the 30 minutes from this time as stated in the question. This gives the final answer of 11 hours and 25 minutes.
See our guide: RPL-PPL-Light-And-Time-Guide (opens in new tab)
During winter in Australia, in what direction from the departure aerodrome will the end of daylight (in LMT) be later?
During winter, the further south you do, the shorter the days get. It will reach a point where it is dark for 24 hours once you get to Antarctica. Therefore, in the southern hemisphere winter, travelling north will increase the length of the days, creating a later MLT.
During winter, the further south you do, the shorter the days get. It will reach a point where it is dark for 24 hours once you get to Antarctica. Therefore, in the southern hemisphere winter, travelling north will increase the length of the days, creating a later MLT.
You plan to fly from NARRABRI (YNBR) (3019S 14950E) direct to ST GEORGE (YSGE) (2803S 14836E). To avoid clouds after departing YNBR you divert left of planned TR along the YNBR – WALGETT railway line. At WEE WAA township (approximately 20 nm WNW YNBR) you decide to track direct to YSGE. The forecast wind for your cruise level is 100/20 kts, and your TAS is 140 kts. The HDG (M) to steer to YSGE is closest to:
The HDG from WEE WAA is 332°
The wind is 100/20
Grab your flight computer.
1. Set TAS triangle to 14 which represents 140
2. 332 degrees has taken magnetic variation into account. Make sure to +/- variation off your drawn track.
3. Turn green circle to 332 for new heading, you can now see approx 16kt xwind and approx 12 kt tailwind.
4. Go around outer scale to 16, come in one circle to get drift adjustment of between 6° and 7°
Answer: New heading = approx 332° + 6° = 338°
The HDG from WEE WAA is 332°
The wind is 100/20
Grab your flight computer.
1. Set TAS triangle to 14 which represents 140
2. 332 degrees has taken magnetic variation into account. Make sure to +/- variation off your drawn track.
3. Turn green circle to 332 for new heading, you can now see approx 16kt xwind and approx 12 kt tailwind.
4. Go around outer scale to 16, come in one circle to get drift adjustment of between 6° and 7°
Answer: New heading = approx 332° + 6° = 338°
CASA Sample Exam Progress
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