Sample PPL Pilot Practice Exam
Please note, this sample exam is a very limited sample of EASIER QUESTIONS
INSTRUCTIONS – select answer > press check (on right) > do all questions > press quiz summary > press finish
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PPL Practice Exam
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Question 1 of 20
1. Question
The red axis is called the?
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Question 2 of 20
2. Question
You plan to fly from NARRABRI (YNBR) (3019S 14950E) direct to ST GEORGE (YSGE) (2803S 14836E). To avoid clouds after departing YNBR you divert left of planned TR along the YNBR – WALGETT railway line. At WEE WAA township (approximately 20nm WNW YNBR) you decide to track direct to YSGE. Which of the following features would provide the most accurate ground speed check between WEE WAA and YSGE?Correct
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Question 3 of 20
3. Question
What parts of the aircraft are represented by numbers 13, 14 and 15?
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Question 4 of 20
4. Question
Given: W/V = 250M/30. Runways available are 03/21 and 09/27. Which runway has the greatest headwind component for landing?
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Question 5 of 20
5. Question
Rotation around the green axis is caused by which control surface?
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Question 6 of 20
6. Question
The shape of an airfoil has no effect on lift produced. Lift is totally dependent on airspeed and angle of attack?
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Question 7 of 20
7. Question
In the above alpha loading chart:
What is the basic empty moment index?
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Question 8 of 20
8. Question
Rotation around the blue axis is called?
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Question 9 of 20
9. Question
Refer : ARFOR / TAF 1 (provided in examination)
Depart YSWG 0500 – YSCB – arrive YMER 0715
Freezing level and visibility forecast for the YSWGYSCB route segment of the flight is?
AREA FORECAST 082300 TO 091100 AREA 21
OVERVIEW:
SURFACE TROUGH AT 0500 YBTH/YSNW STNR
SCATTERED SHOWERS AND THUNDERSTORMS INCLUDING ISOLATED SHOWERS HAIL AND AREAS OF RAIN CONTRACTING EAST
SUBDIVISIONS A: EAST OF THE TROUGH B: WEST OF THE TROUGH
WIND: 2000 A 350/25 B 260/25, 5000 A 340/35 B 260/30, 7000 A 340/35 B 260/30, 10000 A 340/40ms01 B 280/30ms05 …..
CLOUD
AREAS OF BKN ST 1000/3000 COT 3000/5000 LAN
BKN CUSC 5500/11000 ISOL CB TCU 5000/35000 WEST OF RANGES
BKN ACAS ABV 10000
WEATHER:
RASH/TS WITH HAIL CONTRACTING EAST
FOG AFTER 1100
VISIBILITY:
5000M SH/RA 3000M TS
FREEZING LEVEL:
A: 12000 B: 9500
MOD IN CU AND AC SEVERE IN CB AND TCU
TURBULENCE:
MOD IN CLOUD MOD TO SEVERE OVER THE RANGES AND COAST TO 60NM OFFSHORE
TAF YMER 270/130Z 2602/2614 31016/41KT 9999 FEW012 BKN 030 OVC 10000
TEMPO 2600/2604 3000 TS BKN010 SCT050
INTER 2604/2614 5000 SH BKN050
T 18 18 17 15 Q 1003 1003 1004 1008
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Question 10 of 20
10. Question
An aircraft with the call sign VTC567 would be called by saying?
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Question 11 of 20
11. Question
What would be the appropriate label for the letter e on the diagram shown here?
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Question 12 of 20
12. Question
Rotation around the red axis is called?
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Question 13 of 20
13. Question
You are planning a flight in a 4 seater dual control aeroplane with the following passengers: 2 adults and 2 children aged 5 and 8 weighing 20 kg and 40 kg respectively. Assuming aircraft weight limitations will not be exceeded, which of the following limitations apply and why?
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Question 14 of 20
14. Question
Find the ISA deviation if the outside air temp is +30C at 9000ft?
Correct
Well done!
Incorrect
ISA temp at 9000ft = 30 – 2 x 9 = +12

Question 15 of 20
15. Question
Rotation around the green axis is called?
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Question 16 of 20
16. Question
What airspeed can the aircraft operate not only in smooth air, but with some minor turbulence? The aircraft can safely be flown here, making smooth turns, cruising and without excessive control inputs?
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Question 17 of 20
17. Question
Use your E6b or similar flight computer to determine the following approximate TAS?
OAT: 25
Pressure Alt: 19000
CAS: 300
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Question 18 of 20
18. Question
In an aircraft with MTOW less than 5700 kg, which limitation applies to the carriage of cargo?
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Question 19 of 20
19. Question
Calculate the approximate density altitude using the following.
Elevation 3000 FT
QNH 1013
Temp 20ºCCorrect
1. Find pressure height = Elevation + (1013QNH) x 30 e.g. 3000ft at QNH 1013, = 3000+ (10131013) x 30 = 3000+ 0 = 3000 ft
2. For the next part of the calculation ONLY, round pressure height to nearest 500ft
3. Find ISA temp = temp – 2 x the thousands of feet (at the PH) e.g. 20ºC at 3000= 15 – 2 * 3 = 9
4. Take ISA temp away from OAT e.g. 20°C to get ISA deviation = 20° – 9° = 11° ISA dev
5. Multiply ISA deviation by 120 to get pressure correction height e.g. 120 x 11 = 1320 ft
6. Add elevation to pressure correction height to get density altitude e.g. 3000ft + 1320 ft = 4320 ftIncorrect
1. Find pressure height = Elevation + (1013QNH) x 30 e.g. 3000ft at QNH 1013, = 3000+ (10131013) x 30 = 3000+ 0 = 3000 ft
2. For the next part of the calculation ONLY, round pressure height to nearest 500ft
3. Find ISA temp = temp – 2 x the thousands of feet (at the PH) e.g. 20ºC at 3000= 15 – 2 * 3 = 9
4. Take ISA temp away from OAT e.g. 20°C to get ISA deviation = 20° – 9° = 11° ISA dev
5. Multiply ISA deviation by 120 to get pressure correction height e.g. 120 x 11 = 1320 ft
6. Add elevation to pressure correction height to get density altitude e.g. 3000ft + 1320 ft = 4320 ftHint
1. Find pressure height = Elevation + (1013QNH) x 30
2. Round pressure height to nearest 500ft
3. Find ISA temp = temp – 2 x the thousands of feet eg 26C at 2000 = 26 – 2 * 2 = 22
4. Take ISA temp away from OAT to get ISA deviation
5. Multiply ISA deviation by 120 to get pressure correction height
6. Add elevation to pressure correction height for to get density altitude 
Question 20 of 20
20. Question
Calculate the approximate density height using the following.
Elevation 3000 FT
QNH 1020
Temp 4ºCCorrect
1. Find pressure height = Elevation + (1013QNH) x 30 e.g. 3000ft at QNH 1013, = 3000+ (10131020) x 30 = 3000+ 210 = 2790 FT
2. For the next part of the calculation ONLY, round pressure height to nearest 500ft = 3000 FT
3. Find ISA temp = temp – 2 x the thousands of feet (at the PH) e.g. 4ºC at 3000= 15 – 2 * 3 = 9
4. Take ISA temp away from OAT e.g. 4°C to get ISA deviation = 4° – 9° = 5° ISA dev
5. Multiply ISA deviation by 120 to get pressure correction height e.g. 120 x 5 = 600 FT
6. Add elevation to pressure correction height to get density altitude e.g. 2790ft + 600 ft = 2190 FTIncorrect
1. Find pressure height = Elevation + (1013QNH) x 30 e.g. 3000ft at QNH 1013, = 3000+ (10131020) x 30 = 3000+ 210 = 2790 FT
2. For the next part of the calculation ONLY, round pressure height to nearest 500ft = 3000 FT
3. Find ISA temp = temp – 2 x the thousands of feet (at the PH) e.g. 4ºC at 3000= 15 – 2 * 3 = 9
4. Take ISA temp away from OAT e.g. 4°C to get ISA deviation = 4° – 9° = 5° ISA dev
5. Multiply ISA deviation by 120 to get pressure correction height e.g. 120 x 5 = 600 FT
6. Add elevation to pressure correction height to get density altitude e.g. 2790ft + 600 ft = 2190 FT
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